With Chris's algebraic solution, we're sharing four methods of solution to the chickens-and-cows problem. How many chickens and cows have 8 legs and heads altogether?Ĭlearly, 1 chicken and 1 cow have 8 legs and heads altogether. Then each group of 2 chickens and 1 cow would have a total of = 11 legs and heads.ġ6 groups of 2 chickens and 1 cow would have a total of 16 × 11 = 176 legs and heads. Suppose there were exactly twice as many chickens as cows. Method 3 ( Using the 'Make a supposition' strategy) Unless there's a more elegant Sakamoto solution, I find that it doesn't differ much conceptually from its algebraic cousin. Even if they are all cows, they would have only 60 legs and total legs + heads = 15+60 = 75. If number of sheep = 5, number of (chickens + cows) = 15. If number of sheep = 10/14/17, three times would be 30/42/51 but this cannot be the number of (chickens + cows). The farmer is only going to plant grass to wear the. Then, we must have fewer than 25 animals (chickens + cows). Problem Statement: The cow problem started with a farmer who had his cow attached to a 10 x 10 barn at an outside corner by a 100 rope.

Best Sellers Customer Service Prime Todays Deals New. Hello Select your address Books Hello, Sign in. So average number of legs must be more than 3. Chicken, Pig, Cow and the Purple Problem : Ohi, Ruth: : Libri Selezione delle preferenze relative ai cookie Utilizziamo cookie e altre tecnologie simili necessari per consentirti di effettuare acquisti, per migliorare le tue esperienze di acquisto e per fornire i nostri servizi, come descritto in dettaglio nella nostra Informativa sui cookie. Chicken, Pig, Cow and the Purple Problem : Ohi, Ruth, Whamond, Dave: : Books. 25 = chickens + cows)īut we know cows > chickens. Chicken Math, Explained First flock of 14 chickens + 6 chicks 2 goats 32 chickens + 1 guard dog 2 bantams (but bantams only equal a chicken) 50 (ish). So out of 100, we would have 75 legs and 25 heads (i.e. If chicken = cows, average number of legs would be 3 for every head. When I read the question, I note the following:Ĭhickens have 2 legs and one head. 'There are three times the number of chickens and cows than sheep' -> =8. What is the quickest way for this? help pleaseĭivisibility (properties of a multiple) approach can also give an answer quite easily: Solve more than one way to verify the answer. Relate to a similar task and state a math link. Patterns: Cow legs +4 (an even pattern), Chicken legs +2 (an even pattern). The number of chicken legs is half the number of cow legs. The animals include at least one cow, one pig, and one chicken, but no other kind. The farmer saw fewer cows, but the most legs are cow legs. If there are more cows than chickens or sheep, and together, cows and chickens have a total of 100 feet and heads, how many sheep live at the farm? Question 158310: A farmer buys 100 animals for 100.00. Puzzles provoke creativity and show the students how different math concepts and combinations of them can be used to solve problems in unexpected ways. Anything that tickles the brain and improves mathematical thinking. There are three times the number of chickens and cows than sheep. At mathcurious, we love math puzzles and brain teasers.

Cow and chicken math problem